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@ -1337,7 +1337,7 @@ ORDER BY c.cust_name,o.order_num
这是错误的！只对 `cust_name` 进行聚类确实符合题意，但是不符合 `GROUP BY` 的语法。
select 语句中，如果没有 `GROUP BY` 语句，那么 `cust_name`、`order_num` 会返回若干个值，而 `sum(quantity _ item_price)` 只返回一个值，通过 `group by` `cust_name` 可以让 `cust_name` 和 `sum(quantity _ item_price)` 一一对应起来，或者说**聚类**，所以同样的，也要对 `order_num` 进行聚类。
select 语句中，如果没有 `GROUP BY` 语句，那么 `cust_name`、`order_num` 会返回若干个值，而 `sum(quantity * item_price)` 只返回一个值，通过 `group by` `cust_name` 可以让 `cust_name` 和 `sum(quantity * item_price)` 一一对应起来，或者说**聚类**，所以同样的，也要对 `order_num` 进行聚类。
> **一句话，select 中的字段要么都聚类，要么都不聚类**