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Update (1)斐波那契数列问题和跳台阶问题.md
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@ -124,5 +124,4 @@ f(n)=f(n-1)+f(n-2)+...+f(1)
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int b = a << 2;//左移2,等同于16 * 2的2次方,也就是16 * 4
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int c = a >> 2;//右移2,等同于16 / 2的2次方,也就是16 / 4
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