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修改了一些java示例代码的 符号错误。

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This commit is contained in:
kun-li 2020-04-29 16:18:08 +08:00
parent aca369d234
commit c6de3e38f9
1 changed files with 14 additions and 14 deletions
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28
docs/java/basic/final,static,this,super.md
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@ -144,9 +144,9 @@ public class StaticBean {
}
@Override
public String toString() {
return StaticBean{ +
name=' + name + ''' + age + age +
'}';
return "StaticBean{"+
"name=" + name + ",age=" + age +
"}";
}
}
```
@ -155,14 +155,14 @@ public class StaticBean {
public class StaticDemo {
public static void main(String[] args) {
StaticBean staticBean = new StaticBean(1);
StaticBean staticBean2 = new StaticBean(2);
StaticBean staticBean3 = new StaticBean(3);
StaticBean staticBean4 = new StaticBean(4);
StaticBean staticBean = new StaticBean("1");
StaticBean staticBean2 = new StaticBean("2");
StaticBean staticBean3 = new StaticBean("3");
StaticBean staticBean4 = new StaticBean("4");
StaticBean.age = 33;
StaticBean{name='1'age33} StaticBean{name='2'age33} StaticBean{name='3'age33} StaticBean{name='4'age33}
System.out.println(staticBean+ +staticBean2+ +staticBean3+ +staticBean4);
StaticBean.SayHello();Hello i am java
System.out.println(staticBean + " " + staticBean2 + " " + staticBean3 + " " + staticBean4);
//StaticBean{name=1,age=33} StaticBean{name=2,age=33} StaticBean{name=3,age=33} StaticBean{name=4,age=33}
StaticBean.SayHello();//Hello i am java
}
}
@ -233,7 +233,7 @@ public class Singleton {
//将Math中的所有静态资源导入，这时候可以直接使用里面的静态方法，而不用通过类名进行调用
//如果只想导入单一某个静态方法，只需要将换成对应的方法名即可
import static java.lang.Math.;//换成import static java.lang.Math.max;具有一样的效果
import static java.lang.Math.*;//换成import static java.lang.Math.max;具有一样的效果
public class Demo {
public static void main(String[] args) {
@ -262,17 +262,17 @@ class Foo {
}
public static String method1() {
return An example string that doesn't depend on i (an instance variable);
return "An example string that doesn't depend on i (an instance variable)";
}
public int method2() {
return this.i + 1; Depends on i
return this.i + 1; //Depends on i
}
}
```
你可以像这样调用静态方法：`Foo.method1（）`。 如果您尝试使用这种方法调用 method2 将失败。 但这样可行：`Foo bar = new Foo（1）;bar.method2（）;`
你可以像这样调用静态方法：`Foo.method1()`。 如果您尝试使用这种方法调用 method2 将失败。 但这样可行：`Foo bar = new Foo(1);bar.method2();`
总结：