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Merge pull request #2167 from dp0d/patch-2

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Update java-basic-questions-01.md
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@ -509,7 +509,7 @@ Integer i2 = new Integer(40);
System.out.println(i1==i2); System.out.println(i1==i2);
``` ```
`Integer i1=40` 这一行代码会发生拆箱，也就是说这行代码等价于 `Integer i1=Integer.valueOf(40)` 。因此，`i1` 直接使用的是缓存中的对象。而`Integer i2 = new Integer(40)` 会直接创建新的对象。 `Integer i1=40` 这一行代码会发生装箱，也就是说这行代码等价于 `Integer i1=Integer.valueOf(40)` 。因此，`i1` 直接使用的是缓存中的对象。而`Integer i2 = new Integer(40)` 会直接创建新的对象。
因此，答案是 `false` 。你答对了吗？ 因此，答案是 `false` 。你答对了吗？