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Update sql-questions-01.md

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Misaka 2023-03-16 14:51:00 +08:00 committed by GitHub
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@ -1292,13 +1292,13 @@ order by c.cust_name;
select c.cust_name, o.order_num
from Customers c, Orders o
where c.cust_id = o.cust_id
order by c.cust_name;
order by c.cust_name,o.order_num;
# 显式内连接
select c.cust_name, o.order_num
from Customers c inner join Orders o
using(cust_id)
order by c.cust_name;
order by c.cust_name,o.order_num;
```
### 返回顾客名称和相关订单号以及每个订单的总价